A certain freezing process requires that room temperature be lowered from $40^{o} C$ at the rate of $5^{o} C$ every hour. What will be the room temperature $10$ hours after the process begins?

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Solution

To find what will be the room temperature $10$ hours after the process begins
Present temperature $= 10^{\circ} C$

After every hour temperature is lowered at the rate of $5^{\circ} C$

Therefore, in $10$ hours the temperature is lowered by,

$= 5 \times 10^{\circ} C$

$= 50^{\circ} C$

Temperature After 10 hours

$= 40^{\circ} C - 50^{\circ} C$

$= - 10^{\circ} C$

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A certain freezing process requires that room temperature be lowered from 40oC at the rate of 5oC every hour. What will be the room temperature 10 hours after the process begins?

To find what will be the room temperature 10 hours after the process begins Present temperature =10∘CAfter every hour temperature is lowered at the rate of 5∘CTherefore, in 10 hours the temperature is lowered by, =5×10∘C=50∘CTemperature After 10 hours =40∘C−50∘C=−10∘C

A certain freezing process requires that room temperature be lowered from $40^{o} C$ at the rate of $5^{o} C$ every hour. What will be the room temperature $10$ hours after the process begins?