CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A certain laser transition emits 6.37×1015 quanta per second per square meter. The power output in joules per square meter per second would be:
(Given : λ=632.8 nm)

A
5×105 J m2 sec1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2×103 J m2 sec1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
9.2×103 J m2 sec1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2×103 J m2 sec1
We know that,

1 photon has energy, E=hν
n photons will have energy,E=nhν
Given:
n=6.37×1015 photons m2 sec1
λ=632.8 nm=6.32×107 m

Since we have to calculate power in J m2 sec1 and n is given in:
photons m2 sec1, we can write,
P=nhν=nhcλ

We know that,
c=3×108m/s
h=6.63×1034J s
Putting the values, we get
P=2×103 J m2 sec1

flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon