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Question

A certain mass of substance, when dissolved in 100 g C6H6, lowers the freezing point by 1.28 C. The same mass of solute dissolved in 100 g water lowers the freezing point by 1.40 C. If the substance has normal molecular weight in benzene and is completely ionized in water, into how many ions does it dissociate in water? Kf for H2O and C6H6 are 1.86 and 5.12 K kg mol1


Solution

ΔTf=i×m×Kf
For benzene and water respectively:
1.28=1×5.12×n0.11.40=i×1.86×n0.1

So,  i=3.

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