A certain particle carries 2.5 × $10^{- 16}$ C of static electric charge. Calculate the number of electrons present in it.

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Solution

Charge on one electron = 1.6022 × $10^{- 19}$ C
⇒ 1.6022 × $10^{- 19}$ C charge is carried by 1 electron.
∴ Number of electrons carrying a charge of 2.5 × $10^{- 16}$ C
= $\frac{1}{1.6022 \times 10^{- 19} C / e^{-}} (2.5 \times 10^{- 16} C)$
= $1.560 \times 10^{3} e^{-}$
= $1560 e^{-}$

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A certain particle carries 2.5 × 10–16 C of static electric charge. Calculate the number of electrons present in it.

Charge on one electron = 1.6022 × 10–19 C ⇒ 1.6022 × 10–19 C charge is carried by 1 electron. ∴ Number of electrons carrying a charge of 2.5 × 10–16 C =11.6022×10−19C/e−(2.5×10−16C) =1.560×103e− =1560e−

A certain particle carries 2.5 × $10^{- 16}$ C of static electric charge. Calculate the number of electrons present in it.

Charge on one electron = 1.6022 × $10^{- 19}$ C
⇒ 1.6022 × $10^{- 19}$ C charge is carried by 1 electron.
∴ Number of electrons carrying a charge of 2.5 × $10^{- 16}$ C
= $\frac{1}{1.6022 \times 10^{- 19} C / e^{-}} (2.5 \times 10^{- 16} C)$
= $1.560 \times 10^{3} e^{-}$
= $1560 e^{-}$