Question

A charge $$3$$ coulomb experiences a force $$3000\ N$$ when placed in a uniform electric field. The potential difference between two points seperated by a distance of $$1\ cm$$ along the field lines is :

A
10 V
B
90 V
C
1000 V
D
9000 V

Solution

The correct option is A $$10\ V$$ Electric force $$F=qE$$ given, $$F=3000 N, q=3 C$$ $$\therefore E=\dfrac{F}{q}=\dfrac{3000}{3}=1000 V/m$$ Potential difference, $$V={E}{d}$$ where $$d=0.01 m$$ $$\therefore V=1000\times 0.01=10 V$$ Ans:(A) Physics

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