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Question

A charge of $$1\mu C$$ is divided into two parts such that their charges are in the ratio of $$2 : 3$$. These two charges are kept at a distance 1m apart in vaccum. Then, the electric force between them (in newton) is :



A
0.216
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B
0.00216
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C
0.0216
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D
2.16
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Solution

The correct option is A $$0.00216$$

Let the charges be 

$$2q $$ and $$3q $$

$$2q +3q = 1\mu C$$

$$5q = 1\mu C$$

$$q = \dfrac{1}{5}\mu C$$

$$\therefore charges\ are\ \dfrac{2}{5}\mu C \ and\ \dfrac{3}{5}\mu C$$

Force $$= \dfrac{Kq _1 q _2}{r^2}$$

$$= \dfrac{9\times 10^9\times }{1^2}\dfrac{2}{5}\times 10^{-6}\times \dfrac{3}{5}\times 10^{-6}$$

$$= \dfrac{9\times 6\times 10^{-3}}{25}$$

$$= 2.16\times 10^{-3}$$

$$= 0.00216$$


Physics

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