Question

A charge of $2\times {10}^{-2}C$ moves at $30rev/s$ in a circle of diameter $80cm$. The current linked with the circuit in one revolution is

• A. 0.6 A
• B. 1.6 A
• C. 0.2 A
• D. 1.2 A

Answer 1

The correct option is A

0.6 A

Current is given by

$I=\frac{Q}{t}$

The charge in the circuit takes $1s$ to complete $30revolutions$.

So for $1revolution$, it will take $1/30s$.

$I$ = $\frac{2\times {10}^{-2}C}{\frac{1}{30}s}$ = $0.6A$