Question

A charge of 5C experiences a force of 5000 N when it is moved in a uniform electric field. The potential difference between two points separated by a distance of 1 cm is

• A. 10 V
• B. 250 V
• C. 1000 V
• D. 2500 V

Answer 1

The correct option is A 10 V

Charge= $5C$

Force= $5000N$

Distance= $0.01m$

$V=?$

$t=\frac{Force}{q}=\frac{5000}{5}=1000V$

also, $E=\frac{dv}{dr}\Rightarrow dv=E\left(dr\right)=1000\frac{\left(0.01\right)}{100}m$

$v=10V$