CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A charge of magnitude Q is placed at the origin. A second identical charge is placed at the position x=d along the x-axis. Other than infinitely far away, at what position on the x-axis will a positive test charge experience a zero net force?

A
x=d
No worries! Weβ€˜ve got your back. Try BYJUβ€˜S free classes today!
B
x=d2
No worries! Weβ€˜ve got your back. Try BYJUβ€˜S free classes today!
C
x=d2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x=3d2
No worries! Weβ€˜ve got your back. Try BYJUβ€˜S free classes today!
E
Cannot be determined from the given information
No worries! Weβ€˜ve got your back. Try BYJUβ€˜S free classes today!
Open in App
Solution

The correct option is C x=d2
Let the electric field E is zero at a point P between the two given charges , at a distance x from the charge Q which is at the origin .
at point P, electric field due to Q at origin
E1=KQx2
at point P, electric field due to Q at a distance d from Q at origin
E2=KQ(dx)2
as E1 and E2 are in opposite direction due to two positive charges and electric field is zero at point P , therefore
E1=E2

or KQx2=KQ(dx)2

or x2=(dx)2

or x=d2 or 3d2
but x=3d2 is not possible as point P is in between the two charges .
now if we put a positive test charge q at point P , force on it
F=qE=q×0=0
option C is correct .

flag
Suggest Corrections
thumbs-up
0
mid-banner-image
mid-banner-image
Join BYJU'S Learning Program
Select...
similar_icon
Related Videos
thumbnail
lock
Coulomb's Law - Grown-up Version
PHYSICS
Watch in App
Join BYJU'S Learning Program
Select...