A charge +q is placed at a distance 'd' from the centre of the uncharged metallic cube of side 'a' . the electric field at the centre of the cube due to induced charges on the cube will be

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Solution

$A s t h e c h a r g e q i s n o t e n c l o s e d b y m e t a l l i c c u b e o f s i d e a, s o o n c o n s t r u c t i n g G a u s s i a n s u r f a c e, ϕ = \oint E . d A = \frac{0}{ε_{0}} = 0 S o e l e c t r i c f i e l d d u e t o i n d u c e d c h a r g e o f c h a r g e q i s E = 0$

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A charge +q is placed at a distance 'd' from the centre of the uncharged metallic cube of side 'a' . the electric field at the centre of the cube due to induced charges on the cube will be

As the charge q is not enclosed by metallic cube of side a, so onconstructing Gaussian surface, ϕ=∮E.dA=0ε0=0So electric field due to induced charge of charge q is E=0

$A s t h e c h a r g e q i s n o t e n c l o s e d b y m e t a l l i c c u b e o f s i d e a, s o o n c o n s t r u c t i n g G a u s s i a n s u r f a c e, ϕ = \oint E . d A = \frac{0}{ε_{0}} = 0 S o e l e c t r i c f i e l d d u e t o i n d u c e d c h a r g e o f c h a r g e q i s E = 0$