Question

# A charge $$Q$$ is placed at the centre of the line joining two equal charges $$Q$$ . The system of three charges will be in equilibrium , if $$q$$ is equal to

A
Q2
B
Q4
C
4Q
D
+Q2

Solution

## The correct option is B $$-\dfrac{Q}{4}$$System will be in equilibrium , if force between $$Q$$ and $$q$$ +force  between $$Q$$ and $$Q=0$$$$K\dfrac{Q.q}{(r/2)^{2}}+K\dfrac{Q.Q}{r^{2}}=0$$or   $$\dfrac{KQ}{r^2}(4q+Q)=0$$      $$q=-\dfrac{Q}{4}$$Physics

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