Question

# A charge $$Q$$ is uniformly distributed over a long rod $$AB$$ of length $$L$$ as shown in the figure. The electric potential at the point $$O$$ lying at a distance $$L$$ from the end $$A$$ is:

A
3Q4πε0L
B
Q4πε0Lln2
C
Qln24πε0L
D
Q8πε0L

Solution

## The correct option is B $$\dfrac{Q\ln 2}{4\pi\varepsilon _{0}L}$$$$V=\int_{x=L}^{x=2L}\dfrac{k}{x}(\frac{Q}{L})dx=\dfrac{Q\ln 2}{4\pi\varepsilon _{0}L}$$PhysicsNCERTStandard XII

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More