A charged particle is moving with velocity →v in a uniform magnetic field →B. The magnetic force acting on it will be maximum when __________.
A
→v & →B are in same direction
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B
→v & →B are in opposite direction
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C
→v & →B are mutually perpendicular
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D
→v & →B make an angle of 45o with each other
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Solution
The correct option is B→v & →B are mutually perpendicular We know,according to Lorentz force, →F=q[→E+(→v×→B)].
⇒→F=qv×→B(∵→E=0)
⇒→F(magnitude)=qvBsinθ
From here, we can see that magnetic force will be maximum when sinθ is maximum or θ=900.So, the magnetic force acting on it will be maximum when →v and →B are mutually perpendicular.