A cheetah starts from, rest, and accelerates at $2 m / s^{2}$ for $10$ seconds. Calculate :
(a) the final velocity
(b) the distance travelled.

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Solution

Initial velocity, $u = 0 m / s$
Final velocity, $v = ?$
Acceleration, $a = 2 m / s^{2}$
Time, $t = 10 s$
(a) Using, $v = u + a t$
$v = 0 + 2 \times 10 = 20 m / s$
(b) Distance travelled is:
$s = u t + \frac{1}{2} a t^{2}$
$s = 0 \times 10 + \frac{1}{2} \times 2 \times 10 \times 10$
$s = 0 + 100 = 100 m$

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A cheetah starts from, rest, and accelerates at 2m/s2 for 10 seconds. Calculate : (a) the final velocity (b) the distance travelled.

Initial velocity, u=0 m/sFinal velocity, v=?Acceleration, a=2m/s2 Time, t=10s(a) Using, v=u+atv=0+2×10=20m/s(b) Distance travelled is: s=ut+12at2s=0×10+12×2×10×10s=0+100=100m

A cheetah starts from, rest, and accelerates at $2 m / s^{2}$ for $10$ seconds. Calculate :
(a) the final velocity
(b) the distance travelled.