A chemical compound that contains $26$ % nitrogen and $74$ % oxygen has an atomic mass of $108 g / m o l$ . What is the molecular formula of this compound?

N_{3} O_{4}

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{N O}_{2}

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{N O}_{6}

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N_{2} O_{5}

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Solution

The correct option is D $N_{2} O_{5}$
Given, $%$ N in compound $= 26 %,$

$%$ O in compound $= 74 %,$

So, mass of nitrogen in $1 m o l e = \frac{26}{100} \times 108 \approx 28 g$

Mass of oxygen in $1 m o l e = \frac{74}{100} \times 108 \approx 80 g$

So, no. of moles of nitrogen $= \frac{28}{14} = 2 m o l e s$

No. of moles of nitrogen $= \frac{80}{16} = 5 m o l e s$

So, the molecular formula is $N_{2} O_{5}$

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A chemical compound that contains 26% nitrogen and 74% oxygen has an atomic mass of 108 g/mol. What is the molecular formula of this compound?

The correct option is D N2O5Given, % N in compound =26%,% O in compound =74%,So, mass of nitrogen in 1 mole=26100×108≈28 gMass of oxygen in 1 mole=74100×108≈80 gSo, no. of moles of nitrogen =2814=2 molesNo. of moles of nitrogen =8016=5 molesSo, the molecular formula is N2O5

A chemical compound that contains $26$ % nitrogen and $74$ % oxygen has an atomic mass of $108 g / m o l$ . What is the molecular formula of this compound?