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Question

A chemical compound that contains $$26$$% nitrogen and $$74$$% oxygen has an atomic mass of $$108\ g/mol$$. What is the molecular formula of this compound?


A
N3O4
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B
NO2
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C
NO6
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D
N2O5
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Solution

The correct option is D $${ N }_{ 2 }{ O }_{ 5 }$$
Given, $$\%$$ N in compound $$= 26\%,$$

$$\%$$ O in compound $$= 74\%,$$

So, mass of nitrogen in $$1\space mole = \dfrac{26}{100} \times 108 \approx 28\space g$$

Mass of oxygen in $$1\space mole = \dfrac{74}{100} \times 108 \approx 80\space g$$

So, no. of moles of nitrogen $$ = \dfrac{28}{14} = 2\space moles$$

No. of moles of nitrogen $$ = \dfrac{80}{16} = 5\space moles$$

So, the molecular formula is $$N_2O_5$$

Chemistry

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