Question

A chemist synthesized a greenish yellow gaseous compound of chlorine and oxygen and found its density to be $7.71\text{g/L}$ at ${36}^{\circ }\text{C}$ and 2.88 atm. The molecular formula of the compound is:

• A. $Cl{O}_3$
• B. $Cl{O}_2$
• C. $ClO$
• D. $C{l}_2{O}_2$

Answer 1

The correct option is B $Cl{O}_2$

$P=\frac{dRT}{M}\Rightarrow M=\frac{7.71\times 0.082\times 309}{2.88}$
$M=67.83g$
$\therefore$ Molecular formula $=Cl{O}_2$
Because molecular formula of $Cl{O}_2=35.5+2\times 16=67.5g$.
So, the correct answer will be option (b)