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Question

A child is moving on a skateboard at the speed of 2 ms1. After a force acts on him, his speed becomes 3 ms1. Calculate the work done by the force, if the weight of the child is 20 kg.

A
20 J
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B
50 J
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C
100 J
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D
320 J
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Solution

The correct option is B 50 J
Given:
Initial velocity, v1=2 ms1
Final velocity, v2=3 ms1

Using work energy theorem, work done on the boy is equal to the change in his kinetic energy.
W=K2K1
W=mv222mv212
W=20×(94)2
W=50 J

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