CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A circle is inscribed in a quadrilateral ABCD touching its sides AB,BC,CD,AD at P,Q,R and S respectively. If the radius of the circle is 10 cm,BC=38 cm,PB=27 cm and ADCD, then find the length of CD.
1140845_b82e17a4c9e64187974c31e63b831024.png

Open in App
Solution

OP=OS=10 cm
BC=38 cm
PB=27 cm
ADCD

Since, tangent segment to circle from extant point are congruent
Bp=BQ=27 cm
CQ=CR
BC=28 cm
BQ+QC=38
QC=3827=11 cm
Since all angle in Quad DROS are right angle
DROS is a rectangle
OS=RD=10 cm
CD=CR+RD
=CQ+RD
=11+10CD=21 cm



1379648_1140845_ans_c439e67031ce4f0aaf6d6fdab6324d4a.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon