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Question

A circle of radius 2 lies in the first quadrant and touches both the axes of co-ordinates. Then the equation of the circle with centre (6,5) and touching the above circle externally is

A
(x6)2+(y5)2=4
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B
(x6)2+(y5)2=9
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C
(x6)2+(y5)2=36
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D
none of these
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Solution

The correct option is D (x6)2+(y5)2=4
If (h,k) is the center and the radius is r then the equation of the circle is given by (xh)2+(yk)2=r2

Given that The center of the circle (h,k)=(6,5) and the radius r=2

Therefore, the equation of the circle is (x6)2+(y5)2=4

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