Question
A circle of radius 3 cm with centre O is drawn circumscribing a ΔABC. Find OA + OB + OC.
Open in App
Solution
Since the radius of the circle is 3 cm, we have
OA = OB = OC = 3 cm.
Hence, OA + OB + OC = 3 cm + 3 cm + 3 cm = 9 cm.
Since the radius of the circle is 3 cm, we have
OA = OB = OC = 3 cm.
Hence, OA + OB + OC = 3 cm + 3 cm + 3 cm = 9 cm.
Suggest Corrections
0
Similar questions