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Question

A circular coil of 100 turns, radius 10cm carries a current of 5A. It is suspended vertically in a uniform horizontal magnetic field of 0.5T and the field lines make an angle of 60o with the plane of the coil. The magnitude of the torque that make be applied on it to prevent it from turning is?

A
2.93N m
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B
3.43N m
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C
3.93N m
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D
4.93N m
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Solution

The correct option is C 3.93N m
Here, N=100, r=10cm, =0.10m, I=5A,
B=0.5T, θ=90o60o=30o
Area of the coil, A=πr2=3.14×(0.1)2
τ=NIBAsinθ=100×5×0.5×3.14×(0.1)2×sin30o
=3.931Nm

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