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Question

A circular coil of 200 turns and radius 10cm is placed in an uniform magnetic field of 0.1T normal to the plane of the coil. The coil carries a current of 5A. The coil is made up of copper wire of cross-sectional area 105m2 and the number of free electrons per unit volume of copper is 1029. The average force experienced by an electron in the coil due to magnetic field is

A
5×1025N
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B
Zero
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C
8×1024N
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D
None of these
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Solution

The correct option is A 5×1025N
Vd=inqA,

Force=F=q(Vd×B),

F=iBnA=5×0.11029×105=5×1025N

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