A circular coil of radius 4 cm and of 20 turns carries a current of 3 amperes. It is placed in a magnetic field of intensity of $0.5 w e b e r / m^{2}$ . The magnetic dipole moment of the coil is

0.15 a m p e r e - m^{2}

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0.3 a m p e r e - m^{2}

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0.45 a m p e r e - m^{2}

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0.6 a m p e r e - m^{2}

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Solution

The correct option is B $0.3 a m p e r e - m^{2}$
$M = N i A = 20 \times \frac{22}{7} (4 \times 10^{- 2})^{2} 3 = 0.3 A - m^{2}$

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A circular coil of radius 4 cm and of 20 turns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5 weber/m2. The magnetic dipole moment of the coil is

The correct option is B 0.3 ampere−m2M=NiA=20×227(4×10−2)23=0.3 A−m2

A circular coil of radius 4 cm and of 20 turns carries a current of 3 amperes. It is placed in a magnetic field of intensity of $0.5 w e b e r / m^{2}$ . The magnetic dipole moment of the coil is

The correct option is B $0.3 a m p e r e - m^{2}$
$M = N i A = 20 \times \frac{22}{7} (4 \times 10^{- 2})^{2} 3 = 0.3 A - m^{2}$