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Standard XII

Physics

Center of Mass as an Average Point

A circular di...

Question

A circular disc of radius R has a uniform thickness. A circular hole of diameter equal to the radius of disc has been cut out as shown Distance of center of mass of the remaining disc from point O is :-

\frac{R}{14}

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\frac{R}{12}

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\frac{R}{8}

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\frac{R}{6}

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Solution

The correct option is D $\frac{R}{6}$

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A circular disc of radius R has a uniform thickness. A circular hole of diameter equal to the radius of disc has been cut out as shown Distance of center of mass of the remaining disc from point O is :-

The correct option is D R6

The correct option is D $\frac{R}{6}$