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Question

A circular film having radius 2 cm is extended such that its radius becomes 4 cm. If the value of surface tension of the liquid is 0.25 N/m, then the work done in extending the circular film is
  1. 3π×104 J
  2. 4π×104 J 
  3. 6π×104 J 
  4. 8π×104 J 


Solution

The correct option is C 6π×104 J 
The circular film of liquid has two surfaces.
Initial area  Ai=πr2i=4π cm2
Final area Aj=πr2j=16π cm2
ΔA=2(AjAi)
=2(164)π cm2
=24π cm2

We know,
W=T.ΔA
=0.25×24π×104 J
=6π×104 J

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