A circular loop of area 0.02 m $^{2}$ carrying a current of 10A, is held with its plane perpendicular to a magnetic field induction 0.2 T. The torque acting on the loop is:

0.01 Nm

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0.001 Nm

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zero

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0.04 Nm

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Solution

The correct option is D 0.04 Nm
The torque acting on the loop $τ = N I A B cos θ$
where N is the number of turns , I is the current , A is the area of the loop and B is the magnetic field.
Here, $θ = 90^{o}$
$τ = 1 \times 10 \times 0.02 \times 0.2 N m$
On solving we get
$τ = 0.04 N m$

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A circular loop of area 0.02 m2 carrying a current of 10A, is held with its plane perpendicular to a magnetic field induction 0.2 T. The torque acting on the loop is:

The correct option is D 0.04 NmThe torque acting on the loop τ=NIABcosθ where N is the number of turns , I is the current , A is the area of the loop and B is the magnetic field.Here, θ=90o τ=1×10×0.02×0.2NmOn solving we getτ=0.04Nm

A circular loop of area 0.02 m $^{2}$ carrying a current of 10A, is held with its plane perpendicular to a magnetic field induction 0.2 T. The torque acting on the loop is:

The correct option is D 0.04 Nm
The torque acting on the loop $τ = N I A B cos θ$
where N is the number of turns , I is the current , A is the area of the loop and B is the magnetic field.
Here, $θ = 90^{o}$
$τ = 1 \times 10 \times 0.02 \times 0.2 N m$
On solving we get
$τ = 0.04 N m$