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Question

A circular metal plate of radius R is rotating with a uniform angular velocity ω with its plane perpendicular to a uniform magnetic field B. Then the emf developed between the centre and the rim of the plate is

A
πωBR2
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B
ωBR2
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C
πωBR2/2
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D
ωBR2/2
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Solution

The correct option is D ωBR2/2
We write d=Blv (ϵHF)

Now l=dx v=ωx

d=Bωr0xdx

=Bωr22

2032405_1178101_ans_92274ea1df2d40728afef71be9e281fe.png

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