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Question

A circular metal plate of radius $$R$$ is rotating with a uniform angular velocity $$\omega$$ with its plane perpendicular to a uniform magnetic field $$B$$. Then the emf developed between the centre and the rim of the plate is


A
πωBR2
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B
ωBR2
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C
πωBR2/2
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D
ωBR2/2
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Solution

The correct option is D $$\omega BR^{2}/ 2$$
We write $$d\in=Blv$$ $$(\epsilon HF)$$

Now $$l=dx$$   $$v=\omega x$$

$$\displaystyle \int d\in=B\omega \int^r_0 x\,dx$$

$$\boxed{\in =\dfrac{B\omega r^2}{2}}$$

2032405_1178101_ans_92274ea1df2d40728afef71be9e281fe.png

Physics

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