Question

A circus artist is climbing a 30 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the distance of the foot of the pole to the peg in the ground, if the angle made by the rope with the ground level is ${30}^{\circ }$.

• A. 5 m
• B. 15√3 m
• C. 18 m
• D. 20 m

Answer 1

The correct option is B

15√3 m

The figure above represents the given situation.
From the given firgure,
$cos{30}^{\circ }=\frac{BC}{AC}\Rightarrow BC=cos{30}^{\circ }\times AC=\frac{\sqrt{3}AC}{2}=\frac{30\sqrt{3}}{2}=15\sqrt{3}m$