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Question

A cistern can be filled by two pipes aand bin 10and 15hours respectively and is then emptied by a tap in 8hours.If all the taps are opened,then cistern will be fill in how many hours?


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Solution

Pipe ‘a’ fills the cistern in 10hours, so in 1hour the part of cistern filled by pipe a=110

Pipe ‘b’ fills the csitern in 15hours, so in 1hour the part of cistern filled by pipe b=115

A tap can empty the cistern in 8hours, so in 1hour the part of cistern emptied by tap =18

Now if we open all the pipes and taps, then the cistern is filled in 1hour=110+11518=5120=124part

Hence, in1hour,124part of cistern is filled.

Therefore, in 24hours the cistern is completely filled.


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