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Orthoboric Acid

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Question

(a) Classify following oxides as neutral, acidic, basic or amphoteric:

$C O, B_{2} O_{3}, S i O_{2}, C O_{2}, A l_{2} O_{3}, P b O_{2}, T l_{2} O_{3}$

(b)Write suitable chemical equations to show their nature.

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Solution

(1) CO = Neutral

(2) $B_{2} O_{3}$ = Acidic

Being acidic, it reacts with bases to form salts. It reacts with NaOH to form sodium metaborate.

$B_{2} O_{3} + 2 N a O H \to 2 N a B O_{2} + H_{2} O$

(3) $S i O_{2}$ = Acidic

Being acidic, it reacts with bases to form salts. It reacts with NaOH to form sodium silicate.

$S i O_{2} + 2 N a O H \to 2 N A_{2} S i o_{3} + H_{2} O$

(4) $C O_{2}$ = Acidic Being acidic, it reacts with bases to form salts. It reacts with NaOH to form sodium carbonate.

$C O_{2} + 2 N a O H \to N a_{2} C O_{3} + H_{2} O$

(5) $A l_{2} O_{3}$ = Amphoteric Amphoteric substances react with both acids and bases. $A l_{2} O_{3}$ reacts with both NaOH and $H_{2} S O_{4}$ .

$A l_{2} O_{3} + 2 N a O H \to N a A l O_{2}$ + $H_{2} O$

$A l_{2} O_{3} + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3}$ + $3 H_{2} O$

(6) $P b O_{2}$ = Amphoteric Amphoteric substances react with both acids and bases. $P b O_{2}$ reacts with both NaOH and $H_{2} S O_{4}$ .

$P b O_{2} + 2 N a O H \to N a_{2} P b O_{2} + H_{2} O$

$2 P b O_{2} + 2 H_{2} S O_{4} \to 2 P b S O_{4} + 2 H_{2} O + O_{2}$

(7) $T l_{2} O_{3}$ = Basic
Being basic, it reacts with acids to form salts. It reacts with HCl to form thallium chloride.

$T l_{2} O_{3} + 6 H C l \to 2 T l C l_{3} + 3 H_{2} O$

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