Question

A clay sample, originally 25 mm thick at a void ratio of 1.22, was subjected to a compressive load. After the clay sample was completely consolidation, its thickness was measured to be 24 mm. What is the final void ratio?

• A. 1.322
• B. 1.421
• C. 1.311
• D. 1.050

Answer 1

The correct option is D 1.050

$\frac{\Delta H}{H}=\frac{\Delta e}{1+e}$

$\Rightarrow \frac{26-24}{26}=\frac{\Delta e}{1+1.22}$

$\Delta e=0.171$

$But{e}_1-e_2=\Delta e$

$\Rightarrow e_2=1.22-0.171$

$\Rightarrow e_2=1.05$