Question

# A clock, with a brass pendulum, keeps correct time at $$20^\circ C$$, but losses $$8.212 s$$ per day, when the temperature rises to $$30^\circ C$$. The coefficient of linear expansion of brass is:-

A
25×106/C
B
19×106/C
C
20×206/C
D
11×106/C

Solution

## The correct option is B $$19 \times 10^{-6}/^\circ C$$Loss of time in a day= $$\cfrac {1}{2}\times \alpha\times (t_2-t_1)\times 86400$$So, $$8.212= 1/2\times \alpha \times 10 \times 86400$$Answer is $$19 \times 10^{-16}/^oC$$Physics

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