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Question

A clock, with a brass pendulum, keeps correct time at $$20^\circ C$$, but losses $$8.212 s$$ per day, when the temperature rises to $$30^\circ C$$. The coefficient of linear expansion of brass is:-


A
25×106/C
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B
19×106/C
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C
20×206/C
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D
11×106/C
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Solution

The correct option is B $$19 \times 10^{-6}/^\circ C$$
Loss of time in a day= $$\cfrac {1}{2}\times \alpha\times (t_2-t_1)\times 86400$$
So, $$8.212= 1/2\times \alpha \times 10 \times 86400$$
Answer is $$19 \times 10^{-16}/^oC$$

Physics

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