A clock with a metal pendulum beating seconds keeps correct time at 0-C- If it loses 12-5 s a day at 25-C- the coefficient of linear expansion of metal of pendulum is

A clock with a metal pendulum beating seconds keeps correct time at $0^{\circ} C$ . If it loses 12.5 s a day at $25^{\circ} C$ , the coefficient of linear expansion of metal of pendulum is

Q. A clock with a metal pendulum beating seconds keeps correct time at

0^{\circ} C .

If it loses 12.5 seconds a day at

25^{\circ} C,

the coefficient of linear expansion of metal of pendulum is

Q. A seconds metallic pendulum keeps correct time at

0^{\circ} C

. If it loses

12.5 s

a day at

25^{\circ} C

, the coefficient of linear expansion of metal pendulum is

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A clock with a metal pendulum beating seconds keeps correct time at 0∘C. If it loses 12.5 s a day at 25∘C, the coefficient of linear expansion of metal of pendulum is

The correct option is A 186400/∘C Loss of time due to heating a pendulum is given as ΔT = 12αΔθT ⇒ 12.5 = 12 × α × (25−0)∘C × 86400 ⇒ α = 186400 /∘C

A clock with a metal pendulum beating seconds keeps correct time at $0^{\circ} C$ . If it loses 12.5 s a day at $25^{\circ} C$ , the coefficient of linear expansion of metal of pendulum is

The correct option is A
$\frac{1}{86400}$ $/^{\circ} C$

Loss of time due to heating a pendulum is given as $Δ T$ = $\frac{1}{2} α Δ θ T$

$\Rightarrow$ $12.5$ = $\frac{1}{2} \times α \times (25 - 0)^{\circ} C \times 86400$

$\Rightarrow$ $α$ = $\frac{1}{86400}$ $/^{\circ} C$