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Question

A closed tea box has $$47cm \times 47cm \times 60cm$$ internal dimensions, then the total area of tin foil needed for lining it is


A
1.57 m
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B
1.81 m
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C
1.46 m
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D
2.10 m
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Solution

The correct option is C 1.57 m
We have,
$$l=47\ cm, b=47\ cm, h=60\ cm$$

So, the required area
$$=$$ Area of Base $$+$$ Area of Top $$+$$ Lateral surface area of the tea box
$$=l\times b+l\times b+2(l+b)\times h$$
$$=47\times 47+47\times 47+2(47+47)\times 60$$
$$=2209+2209+2\times 94\times 60$$
$$=2209+2209+11280$$
$$=15698\ cm^2$$
$$=1.5698\ m^2$$
$$\approx 1.57\ m^2$$

Hence, this is the answer.

Mathematics

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