Question

A closed tea box has $47cm\times 47cm\times 60cm$ internal dimensions, then the total area of tin foil needed for lining it is

• A. 1.57 m
• B. 1.81 m
• C. 1.46 m
• D. 2.10 m

Answer 1

Answer: (A)

1.57 m

We have,

$l=47cm,b=47cm,h=60cm$

So, the required area

$=$ Area of Base $+$ Area of Top $+$ Lateral surface area of the tea box

$=l\times b+l\times b+2(l+b)\times h$

$=47\times 47+47\times 47+2(47+47)\times 60$

$=2209+2209+2\times 94\times 60$

$=2209+2209+11280$

$=15698c{m}^2$

$=1.5698m^2$

$\approx 1.57m^2$

Hence, this is the answer.