Question

# A closed tea box has $$47cm \times 47cm \times 60cm$$ internal dimensions, then the total area of tin foil needed for lining it is

A
1.57 m
B
1.81 m
C
1.46 m
D
2.10 m

Solution

## The correct option is C 1.57 mWe have,$$l=47\ cm, b=47\ cm, h=60\ cm$$So, the required area$$=$$ Area of Base $$+$$ Area of Top $$+$$ Lateral surface area of the tea box$$=l\times b+l\times b+2(l+b)\times h$$$$=47\times 47+47\times 47+2(47+47)\times 60$$$$=2209+2209+2\times 94\times 60$$$$=2209+2209+11280$$$$=15698\ cm^2$$$$=1.5698\ m^2$$$$\approx 1.57\ m^2$$Hence, this is the answer.Mathematics

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