CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A closed vessel with rigid walls contains 1 mol of $$^{238}_{92}U$$ and 1 mol of air at 298 K. Considering complete decay of $$^{238}_{92}U$$ to $$^{206}_{82}Pb$$, the ratio of the final pressure to the initial pressure of the system at 298 K is:


Solution

$$^{238}_{92}U$$ decays to $$^{206}_{82}Pb$$ by a series of alpha and beta emissions.
The number of alpha particles emitted by 1 $$^{238}_{92}U$$ atom  is $$\dfrac {238-206}{4}=8$$.
Hence 1 mole of $$^{238}_{92}U$$ will produce 8 moles of He.
Initially, only air was present.
Hence, an initial number of moles of gaseous substances $$=1$$ mole.
The final number of moles of gaseous substances $$=1$$ mole air $$+8$$ mole He $$=9$$ moles.
The pressure of the gas is directly proportional to the number of moles of gas.
Hence, the ratio of the final pressure to the initial pressure of the system at 298 K is $$9:1$$.

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image