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Question

A coil having 12 turns is connected to a battery. The magnetic field at the axis of the helix will be greater compared to the magnetic field at the centre of a circular loop of the same radius carrying current. How and why?
Please explain in simple words as I can't understand it in the app.


Solution

For a helix with 12 turns,
N=12
Magnetic field at its axis = (µi / 2πr) x N
B'= (µi / 2πr) x 12

For a circular loop,
N=1

Magnetic field at its axis = (µi / 2πr) x N  [ given radius and current is the same ]
B = (µi / 2πr) x 1
B = (µi / 2πr)

Hence B' = 12 times B
So, B' > B

Therefore,
the magnetic field at the axis of the helix will be greater compared to the magnetic field at the centre of a circular loop of the same radius carrying current.
 

Physics

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