Question

# A coil having resistance 40Ω, number of turns 100 and radius 6 mm is connected to an ammeter of resistance 160Ω. The coil is placed perpendicular to the magnetic field. When the coil is taken out of the field, a charge of 32μC passes through it. The intensity of magnetic field will be

A
6.55 T
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B
5.66 T
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C
0.655 T
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D
0.566 T
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Solution

## The correct option is C 0.566 TGiven: Radius r=6mmResistance of coil =40 ΩNumber of turns =100Resistance of ammeter =160 ΩTotal resistance R=200 ΩCharge q=32×10−6CSolution: We know the induced emf isζ=ΔϕΔtIR=Δ(BA)ΔtΔQΔtR=δ(B⋅A)ΔtΔB=ΔQ⋅RAThe area isA=Nπr2A=100×3.14×(6×10−3)2A=0.011304The magnetic flux density isΔB=32×10−6×2000.011304ΔB=0.566THence, The magnetic flux density is 0.566 T.So,the correct option:D

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