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Question

A coil having resistance 40Ω, number of turns 100 and radius 6 mm is connected to an ammeter of resistance 160Ω. The coil is placed perpendicular to the magnetic field. When the coil is taken out of the field, a charge of 32μC passes through it. The intensity of magnetic field will be

A
6.55 T
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B
5.66 T
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C
0.655 T
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D
0.566 T
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Solution

The correct option is C 0.566 T
Given: Radius r=6mm
Resistance of coil =40 Ω
Number of turns =100
Resistance of ammeter =160 Ω
Total resistance R=200 Ω
Charge q=32×106C
Solution: We know the induced emf is
ζ=ΔϕΔt
IR=Δ(BA)Δt
ΔQΔtR=δ(BA)Δt
ΔB=ΔQRA
The area is
A=Nπr2
A=100×3.14×(6×103)2
A=0.011304
The magnetic flux density is
ΔB=32×106×2000.011304
ΔB=0.566T
Hence, The magnetic flux density is 0.566 T.
So,the correct option:D

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