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Question

# A coil in the shape of an equilateral triangle of side 0.02 m is suspended from the vertex such that it is hanging in a vertical plane between the role-pieces of a permanent magnet producing a horizontal magnetic field of 5×10−2T. When a current of 0.1 A passed through it and the magnetic field is parallel to its plane through couple acting on the coil is:-

A
8.65×107Nm
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B
6.65×107Nm
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C
3.35×107Nm
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D
3.91×107Nm
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Solution

## The correct option is A 8.65×10−7N−mGiven,Side of equilateral triangle, a=0.02mMagnetic fiels, B=5×10−2TCurrent passed through the coil, I=0.1AAs the coils is in the form of an eqiuilateral triangle, its area is,A=√34×0.02×0.02A=√3×10−4mTorque on current carrying coil in magnetic field is,τ=BINAsinαwhere,α=900 and N=1Then,τ=BIA5×10−2×0.1×√3×10−4N−m=8.65×10−7N−m

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