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Question

A coil of inductance 5.0 mH and negligible resistance is connected to an alternating voltage V=10sin(100t). The peak current in the circuit will be:

A
2 amp
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B
1 amp
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C
10 amp
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D
20 amp
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Solution

The correct option is D 20 amp
Inductive reactance XL=ωL=100×5×103=0.5Ω

Vmax=Peak Voltage=10V

Peak Current Ip=PeakVoltageXL=100.5=20Amps


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