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Question

A coil of resistance 40Ω is connected to a galvanometer of 160Ω resistance. The coil has radius 6mm and turns 100. This coil is placed between the poles of a magnet such that magnetic field is perpendicular to coil. If coil is dragged out then the charge through the galvanometer is 32μC. The magnetic field is?

A
6.55 T
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B
5.66 T
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C
0.655 T
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D
0.566 T
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Solution

The correct option is D 0.566 T
Induced emf, e= dϕdt------ (1)
where, dϕ is the change in flux
As we now, emf= I×R

(1)=> IR= d(BA)dt [Magnetic flux Φ= BA]

=> dQdt×R=d(BA)dt

=>dB= dQ.RA

Given, dQ= 32×106 C

R= (40+160)Ω= 200Ω

A=n(πR2)
n= no.s of turns of coil= 100 (given)

A=100×3.14×(6×103)2 m2

Hence, dB=32×106×2001003.14×36×106T
= 0.566T

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