Question

A coin is tossed 1000 times with the following frequencies

Head: 455, Tail: 545.

Compute the probability for each event

Answer 1

Total number of events (m) =1000

(i) Event A: getting a head.

possible events (m) = 455

$\therefore$ probability P(A) =$\frac{m}{n}=\frac{455}{1000}$

=$\frac{91}{200}=0.455$

(ii) Event B: getting a tail.

possible events (m) =545

$\therefore$ P(B) =$\frac{m}{n}=\frac{545}{1000}=\frac{109}{200}=0.545$