Question

A coin is tossed 50 times and the tail appears 28 times. In a single throw of a coin, what is the probability of getting a head?

Answer 1

Total number of trials = 50
Number of times the tail appears = 28

So, number of times the head appears = 50 − 28 = 22

Let E be the event of getting a head. Then,
P(getting a head) = P (E) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{times}\mathrm{head}\mathrm{appears}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{trials}}=\frac{22}{50}=\frac{11}{25}$