Question

a coin is tossed two times find the probability of getting at least one tail

Answer 1

Dear Student,
When a coin is tossed twice, the sample space(including all permutations and combinations) will be HH,HT,TH,TT.
i.e n(S)=4.
Let A be the event of getting atleast one tail(i.e one or more than one).
The possible combinations would be HT,TH,TT, i.e n(A)=3.
Thus the probability,P(A) would be n(A)/n(S)=3/4=0.75.
Thus the required probability is 0.75.
Regards.