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Question

A colourless crystalline salt $$'X'$$ is soluble in dilute $$HCl$$. On adding $$NaOH$$ solution, it gives a white precipitate which is insoluble in excess of $$NaOH$$. $$'X'$$ is :


A
Al2(SO4)3
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B
ZnSO4
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C
MgSO4
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D
SnCl2
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Solution

The correct option is D $$MgS{ O }_{ 4 }$$
$$MgS{ O }_{ 4 }$$ is soluble in HCl and gives $$MgCl_2 + H_2SO_4(aq)$$
$$MgSO_4(s) + 2 HCl(aq)\rightarrow MgCl_2 + H_2SO_4(aq)$$
$$Mg^{2+}(aq) + 2Cl^{-}(aq) + Na^{+}(aq) + OH^{-}(aq)\rightarrow Mg(OH)_2(s) + Na^{+}(aq) + Cl^{-}(aq)$$ 
Then, find the net ionic equation by cancelling out any species that appear on both sides of the equation. 
$$Mg^{2+}(aq) + 2OH^{-}(aq)\rightarrow Mg(OH)_2(s)$$
A colourless crystalline salt X is soluble in dilute HCl On adding $$NaOH$$ solution, it gives a white precipitate ($$Mg(OH)_2$$) which is insoluble in excess of $$NaOH$$. X is $$MgS{ O }_{ 4 }$$
Hence option C is correct.

Chemistry

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