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Question

A company manufactures two articles A and B. There are two department through which these article are processed : (i) assembly and (ii) finishing department. The maximum capacity of the first department is 60 hours a week and that of other department. 48 hours, per week. The product of each unit of article A requires 4 hours in assembly and 2 hours in finishing and that of each unit of B requires 2 hours in assembly and 4 hours in finishing. If the profit is Rs. 6 for each unit A and Rs. 8 for each unit of A and Rs. 8 for each unit of B, find the number of units of A and B to be produced per week in order to have maximum profit.

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Solution

Let the number of type A and B articles produced be x and y respectively.
Each unit of article A requires 4 hours in assembly and 2 hours in the finishing department.
Total time taken by x units of article A in assembly department =4x
Total time taken by x units of article A in finishing department =2x
Each unit of article B requires 2 hours in assembly and 4 hours in the finishing department.
Total time taken by y units of article B in assembly department =2y
Total time taken by y units of article B in finishing department =4y
Maximum capacity of assembly department = 60hours/week
Maximum capacity of finishing department = 48hours/week
Profit on article A = Rs.6/unit
Profit on article B = Rs.8/unit
Total profit in a week = 6x+8y
Thus the required constraints are-
4x+2y60 .............(i)
2x+4y48 .............(ii)
x0,y0 .............(iii)
Max Z=6x+8y
Plotting these inequations on the graph we get the following corner points-
A(0,12) ; B(12,6) ; C(15,0)
At A, Z=6×0+8×12=96
At B, Z=6×12+8×6=72+48=120
At C, Z=6×15+8×0=90
Thus, Z is maximum at B(12,6)
Thus, 12 units of article A and 6 units of article B should be produced to get the maximum profit per week.

1621833_1665239_ans_a0c37eed65e2480cad86bd3fdae4ee68.PNG

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