Let the number of type
A and
B articles produced be
x and
y respectively.
Each unit of article A requires 4 hours in assembly and 2 hours in the finishing department.
Total time taken by x units of article A in assembly department =4x
Total time taken by x units of article A in finishing department =2x
Each unit of article B requires 2 hours in assembly and 4 hours in the finishing department.
Total time taken by y units of article B in assembly department =2y
Total time taken by y units of article B in finishing department =4y
Maximum capacity of assembly department = 60hours/week
Maximum capacity of finishing department = 48hours/week
Profit on article A = Rs.6/unit
Profit on article B = Rs.8/unit
Total profit in a week = 6x+8y
Thus the required constraints are-
4x+2y≤60 .............(i)
2x+4y≤48 .............(ii)
x≥0,y≥0 .............(iii)
Max Z=6x+8y
Plotting these inequations on the graph we get the following corner points-
A(0,12) ; B(12,6) ; C(15,0)
At A, Z=6×0+8×12=96
At B, Z=6×12+8×6=72+48=120
At C, Z=6×15+8×0=90
Thus, Z is maximum at B(12,6)
Thus, 12 units of article A and 6 units of article B should be produced to get the maximum profit per week.