A compound 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96 g. What are its emperical formula and molecular formula?

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Solution

Hydrogen Carbon Chlorine
mass 4.07 24.27 71.65
RAM 1 12 35.5
no. of moles 4.07/1 24.27/12 71.65/35.5
4.07 2.02 2.02
divide by the 4.07/2.02 2.02/2.02 2.02
least no 2 1 1

Empirical formula therefore is H2CCl

the molecular formula is (EF)n=MF

(1+1+12+35.5)=49.5......98.96/49.5=2 n=2

(H2CCl)2=H4C2Cl2

therefore the molecular formula is C2H4Cl2 (dichloroethane)

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