A compound ‘A′ with the empirical formula C3H6O2 has a fruity smell. It reacts with DIBAL−H/H2O at ultra low temperatures. After work-up, we get ‘X′ and ‘Y′. ‘X′ on treating with dilute NaOH forms ‘Z′. ′Z′ doesn’t have a hydroxyl group and it reacts with (CH3)2CuLi to give M. ‘Z′ also reacts with CH3MgBr to give ‘N′. Based on this passage, answer the following questions:
Which of the following is/are true?
‘M′ has a carbon-carbon double bond
‘M′ is a carbonyl compound
‘N′ has a carbon carbon double bond