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Question

A concave mirror of focal length f and diameter d(d<<f) is kept horizontally and filled with water. Rays of light parallel to the mirror axis are incident on it. After reflection, the rays will focus close to

A
0.25f
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B
1.33f
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C
f
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D
0.75f
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Solution

The correct option is A 1.33f

The correct option is (D).

The focal length of the given Plano-convex lens is

1fL=(μ1)[1R11R2]=(431)[11(2f)]

fL=6f

Now the equivalent Power is given as combination power PL of lens and Pm of mirror, hence

Peq=2PL+Pm=2(16f)+1f=43f

Hence,

feq=3f4=1.33f

2004412_1496380_ans_3ed373927c484537a051c86fba79763f.png

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