CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A concave mirror of radius of curvature R is moving towards object of mass m with constant velocity V0. Mirror make elastic collision with object at pole at t = 0. Mass of mirror is very large compare to mass of object. Column-1 Shown time, Column-2 shows speed of image of object, column-3 shows distance of image from pole of mirror at given time (D1)



Column 1Column 2Column 3(I)t=R4V0(i)V1=89V0(P)D1=3R(II)t=3R5V0(ii)V1=24V0(Q)D1=R2(III)t=RV0(iii)V1=3V0(R)D1=23R(IV)t=2RV0(iv)V1=0(S)D1=R

Which of the following correctly matched



 
  1. (II) (iv) (S)
  2. (III) (iii) (P)
  3. (I) (ii) (P)
  4. (I) (iii) (Q)


Solution

The correct option is D (I) (iii) (Q)

To perceive this we can go on the reference of the mirror, then it will be analogous to the situation where a ball hits a wall elastically.
at t=R4V0u=R4

V=ufuf(R4)(R2)R4+R2=R2 

V1=(m)2V0+V0=(2)2V+V=3V Here m is velocity magnification i.e v2u2

Now, at t=3R5V0 u=3R5

V=4fuf  V=3R D1=|V|=3R

V1=(5)2V0+V0=24V0

at t=RV0u=R

V=R  D1=|V|=R

V1=(1)2V0+V0=0

at t=2RV0  u=2R

V=ufuf=23R  M=Vu=13

V1=(13)2  V0+V0=89V0

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image