The correct option is C 2 L
Let the mass of the H2SO4 solution be 100 g.
98% by mass means 98 g of H2SO4 is present in 100 g of solution.
Number of moles of H2SO4=given massmolar mass
We know, Density=massvolume
So, volume of the solution=1001.84 mL
Molarity=number of moles of solutevolume of solution in mL×1000
Let the volume of 18.4 M acid be V L.
So, conserving moles before and after dilution:
where, M2 and V2 are the final concentration and volume,
Volume of 18.4 M H2SO4 required is 2L.